The following code demonstrates the
% We iterate five times
for i = 1 : 5
% Let's ask the user to enter digits one-by-one
str = ['Give me digit number ' num2str(i) ': '];
s(i) = input(str,'s');
% and we reverse the digits, starting by the end
p(6 - i) = s(i);
end
for i = 1 : 5
% Let's ask the user to enter digits one-by-one
str = ['Give me digit number ' num2str(i) ': '];
s(i) = input(str,'s');
% and we reverse the digits, starting by the end
p(6 - i) = s(i);
end
% Compare the entered string with the reversed one
if s == p
% and answer accordingly
disp ('WOW! Those digits happen to be a palindrome!')
else
disp ('They are NOT a palindrome, sorry...')
end
if s == p
% and answer accordingly
disp ('WOW! Those digits happen to be a palindrome!')
else
disp ('They are NOT a palindrome, sorry...')
end
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